x^2+32x-380=0

Solution for x^2+32x-380=0 equation:

x^2+32x-380=0

a = 1; b = 32; c = -380;
Δ = b2-4ac
Δ = 322-4·1·(-380)
Δ = 2544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2544}=\sqrt{16*159}=\sqrt{16}*\sqrt{159}=4\sqrt{159}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-4\sqrt{159}}{2*1}=\frac{-32-4\sqrt{159}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+4\sqrt{159}}{2*1}=\frac{-32+4\sqrt{159}}{2}
$